1. How many factors does 12 have? | Easy |
A. 4 B. 6 C. 8 D. None of these |
View Answer
Answer: Option B
Explanation:
12 can be expressed in terms of its prime factors as 22 * 31.
-> Number of factors = (2+1) * (1+1) = 6
Note: The 6 factors are: 1,2,3,4,6,12
2. Find the number of divisors of 15876, excluding the number itself. | Easy |
A. 34 B. 44 C. 56 D. None of these |
View Answer
Answer: Option B
Explanation:
15876 = 22 * 34 * 72
-> Number of factors (divisors) = (2+1)*(4+1)*(2+1) = 45
However, these 45 factors also include 15876 as a factor. Hence there will be 45-1=44 factors excluding the number itself.
3. Find the number of ways in which 24 can be written as a product of two co-prime factors. | Easy |
A. 1 B. 2 C. 3 D. None of these |
View Answer
Answer: Option B
Explanation:
24 = 23 * 31
-> 24 has two prime factors, 2 and 3
-> 24 can be written as a product of two co-prime factors in 2(2-1) or 2 ways.
Note: The two ways of writing 24 as a product of two co-prime factors are (1*24) and (3*8)
4. In how many ways can 9216 be expressed as a product of 2 factors? | Medium |
A. 15 B. 16 C. 17 D. None of these |
View Answer
Answer: Option C
Explanation:
Let N be a perfect square, such that N = √N * √N = ap * bq * cr
Then N can be expressed as a product of 2 factors in ((p+1) *(q+1) *(r+1) +1))/2 ways
Now, 9216 = 96*96 = 32 * 210
-> It can be expressed as a product of 2 factors in ((2+1)*(10+1)+1))/2 = 17 ways
5. Find the sum of all factors of 8064. | Easy |
A. 13260 B. 26520 C. 39780 D. None of these |
View Answer
Answer: Option B
Explanation:
8064 = 27 * 32 * 71
-> Sum = ((28-1)/(2-1)) * ((33-1)/(3-1)) * ((72-1)/(7-1)) = (255*26*48)/(2*6) = 26520
6. What is the sum of all factors of 36? | Easy |
A. 55 B. 91 C. 93 D. None of these |
View Answer
Answer: Option B
Explanation:
36 can be expressed in terms of its prime factors as 22 * 32
-> Sum of all factors of 36 = (1+2+22) (1+3+32) = 91
Note:
The various factors of 36 are: 1,2,3,4,6,9,12,18,36
7. What is the number of odd and even factors of 540? | Medium |
A. 7, 15 B. 8, 14 C. 9, 16 D. None of these |
View Answer
Answer: Option D
Explanation:
540 = 22 * 33 *5
-> Total number of factors of 540 = (2+1) (3+1) (1+1) = 24
-> Number of odd factors will include all factors without 2 = Number of ways in which we can select powers of 3 and 5.
Now, powers of 3 can be selected in 4 ways i.e. 30, 31, 32 and 33 and powers of 5 can be selected in 2 ways i.e. 50 and 51. Hence number of odd factors = 4 * 2 = 8. Also, number of even factors = 24-8 = 16
8. What is the sum of all odd factors of 540? What is the sum of all even factors of 540? | Difficult |
A. 240, 1680 B. 220, 1440 C. 240, 1440 D. None of these |
View Answer
Answer: Option C
Explanation:
540 = 22 * 33 *5
Odd factors will be all those factors which are devoid of 2.
-> Sum of all these factors will be (1+31+32+33) (1+51) = 240
Also, sum of all factors of 540 = (1+21+22) (1+31+32+33) (1+51) = 7 * 40 * 6 = 1680
Sum of even factors = 1680 – 240 = 1440
9. How many factors of 270 are perfect squares? | Difficult |
A. 2 B. 3 C. 4 D. None of these |
View Answer
Answer: Option A
Explanation:
270 = 2 * 33 * 5
For any perfect square, all the powers of the prime factors have to be even numbers. So, if the factor is of the form 2a * 3b * 5c,
then a can take 1 value: 0; b can take 2 values: 0 and 2; and c can take 1 value: 0.
Thus, there are 2 possibilities in all: 20*30*50 and 20*32*50 i.e. 1 and 9
10. The sum of all factors of a number, including 1 and the number itself, is 124. How many such numbers exist? | Difficult |
A. 1 B. 2 C. 3 D. None of these |
View Answer
Answer: Option B
Explanation:
Let the number be N.
Then, sum of all factors of N = (1 + A1 + A2 + A3 + …+ Ap) (1 + B1 + B2 + B3 + …+ Bq) (1 + C1 + C2 + C3 + …+ Cr), where N= Ap * Bq *Cr ; A, B and C are prime factors of N, and p, q and r are their respective powers.
-> (1 + A1 + A2 + A3 + …+ Ap) (1 + B1 + B2 + B3 + …+ Bq) (1 + C1 + C2 + C3 + …+ Cr) = 124
Now, 124 can be expressed as a product of its prime factors in the following ways:
124 = 22 * 31 = (1+3) (1+2+22+23+24) OR (1+3) (1+5+52)
Thus, A=3, B = 2, p = 1, q = 4 OR A =3, B = 5, p = 1, q = 2
-> N = 3 * 24 = 48 OR 3 * 52 = 75
Hence, the required number is either 48 OR 75.