1. How many factors does 12 have? Easy
A. 4
B. 6
C. 8
D. None of these

View Answer

Answer: Option B

Explanation:

12 can be expressed in terms of its prime factors as 22 * 31.

-> Number of factors = (2+1) * (1+1) = 6

Note: The 6 factors are: 1,2,3,4,6,12

2. Find the number of divisors of 15876, excluding the number itself. Easy
A. 34
B. 44
C. 56
D. None of these

View Answer

Answer: Option B

Explanation:

15876 = 22 * 34 * 72

-> Number of factors (divisors) = (2+1)*(4+1)*(2+1) = 45

However, these 45 factors also include 15876 as a factor. Hence there will be 45-1=44 factors excluding the number itself.

3. Find the number of ways in which 24 can be written as a product of two co-prime factors. Easy
A. 1
B. 2
C. 3
D. None of these

View Answer

Answer: Option B

Explanation:

24 = 23 * 31

-> 24 has two prime factors, 2 and 3

-> 24 can be written as a product of two co-prime factors in 2(2-1) or 2 ways.

 

Note: The two ways of writing 24 as a product of two co-prime factors are (1*24) and (3*8)

4. In how many ways can 9216 be expressed as a product of 2 factors? Medium
A. 15
B. 16
C. 17
D. None of these

View Answer

Answer: Option C

Explanation:

Let N be a perfect square, such that N = √N * √N = ap * bq * cr

Then N can be expressed as a product of 2 factors in ((p+1) *(q+1) *(r+1) +1))/2 ways

Now, 9216 = 96*96 = 32 * 210

-> It can be expressed as a product of 2 factors in ((2+1)*(10+1)+1))/2 = 17 ways

5. Find the sum of all factors of 8064. Easy
A. 13260
B. 26520
C. 39780
D. None of these

View Answer

Answer: Option B

Explanation:

8064 = 27 * 32 * 71

-> Sum = ((28-1)/(2-1)) * ((33-1)/(3-1)) * ((72-1)/(7-1)) = (255*26*48)/(2*6) = 26520

6. What is the sum of all factors of 36? Easy
A. 55
B. 91
C. 93
D. None of these

View Answer

Answer: Option B

Explanation:

36 can be expressed in terms of its prime factors as 22 * 32

-> Sum of all factors of 36 = (1+2+22) (1+3+32) = 91

Note:

The various factors of 36 are: 1,2,3,4,6,9,12,18,36

7. What is the number of odd and even factors of 540? Medium
A. 7, 15
B. 8, 14
C. 9, 16
D. None of these

View Answer

Answer: Option D

Explanation:

540 = 22 * 33 *5

-> Total number of factors of 540 = (2+1) (3+1) (1+1) = 24

-> Number of odd factors will include all factors without 2 = Number of ways in which we can select powers of 3 and 5.

Now, powers of 3 can be selected in 4 ways i.e. 30, 31, 32 and 33 and powers of 5 can be selected in 2 ways i.e. 50 and 51. Hence number of odd factors = 4 * 2 = 8. Also, number of even factors = 24-8 = 16

8. What is the sum of all odd factors of 540? What is the sum of all even factors of 540? Difficult
A. 240, 1680
B. 220, 1440
C. 240, 1440
D. None of these

View Answer

Answer: Option C

Explanation:

540 = 22 * 33 *5

Odd factors will be all those factors which are devoid of 2.

-> Sum of all these factors will be (1+31+32+33) (1+51) = 240

Also, sum of all factors of 540 = (1+21+22) (1+31+32+33) (1+51) = 7 * 40 * 6 = 1680

Sum of even factors = 1680 – 240 = 1440

9. How many factors of 270 are perfect squares? Difficult
A. 2
B. 3
C. 4
D. None of these

View Answer

Answer: Option A

Explanation:

270 = 2 * 33 * 5

For any perfect square, all the powers of the prime factors have to be even numbers. So, if the factor is of the form 2a * 3b * 5c,

then a can take 1 value: 0; b can take 2 values: 0 and 2; and c can take 1 value: 0.

Thus, there are 2 possibilities in all: 20*30*50 and 20*32*50 i.e. 1 and 9

10. The sum of all factors of a number, including 1 and the number itself, is 124. How many such numbers exist? Difficult
A. 1
B. 2
C. 3
D. None of these

View Answer

Answer: Option B

Explanation:

Let the number be N.

Then, sum of all factors of N = (1 + A1 + A2 + A3 + …+ Ap) (1 + B1 + B2 + B3 + …+ Bq) (1 + C1 + C2 + C3 + …+ Cr), where N= Ap * Bq *Cr ; A, B and C are prime factors of N, and p, q and r are their respective powers.

-> (1 + A1 + A2 + A3 + …+ Ap) (1 + B1 + B2 + B3 + …+ Bq) (1 + C1 + C2 + C3 + …+ Cr) = 124

Now, 124 can be expressed as a product of its prime factors in the following ways:

124 = 22 * 31 = (1+3) (1+2+22+23+24) OR (1+3) (1+5+52)

Thus, A=3, B = 2, p = 1, q = 4 OR A =3, B = 5, p = 1, q = 2

-> N = 3 * 24 = 48 OR 3 * 52 = 75

Hence, the required number is either 48 OR 75.