| 1. M, N, S & T are four friends and their ages are 52, 43, 57 and 47 years, not necessarily in that order. When asked about their age, they lie with respect to their own age, but speak the truth regarding the ages of their friends. Following are the statements made by them: S says, “My age is 52 and M’s age is not 57.” N says, “My age is not 47, and S’s age is not 43.” M says, “My age is 52.” What is T’s age? |
Easy |
| A. 43 B. 52 C. 47 D. 57 |
View Answer
Answer: Option B
Explanation:
As per M’s statement, his age can be either 43, 57 or 47 —– ❶
As per N’s statement, his age is 47, and S’s age can’t be 43 —– ❷
As per S’s statement M can’t be 57, and he can’t be 52 —– ❸
From ❷ N is 47, from ❸, M can’t be 57 and from ❶ therefore M’s age is 43 —– ❹
Also, from ❸ can’t be 52, so his age is 57 and T’s age is 52.
| 2. P, Q and R play some games such that: i. P starts the first game, Q starts the second game, R starts the third game and then this sequence is repeated for the next three games and so on until they stopped playing. ii. The person who starts the game does not win that game. iii. No one wins two consecutive games. iv. They continued playing till one of them wins three games. v. The person who wins more than two games does not win the first game. Who wins more than two games? |
Difficult |
| A. P B. Q C. R D. Can’t be determined |
View Answer
Answer: Option C
Explanation:
The following possibilities arise:
| P starts | Q starts | R starts | P starts | Q starts | R starts | P starts | Person winning more than two games (3) | |
| 1 | Q | R | P | Q | R | P | Q | Q |
| 2 | Q | R | P | Q | R | P | R | R |
| 3 | Q | R | P | Q | R | Q | – | Q |
| 4 | Q | R | P | Q | P | Q | Q | |
| 5 | Q | R | P | R | P | Q | R | R |
| 6 | Q | R | Q | R | P | Q | – | Q |
| 7 | Q | P | Q | R | P | Q | – | Q |
| 8 | R | P | Q | R | P | Q | R | R |
In the above table, each of the cells represents the winner for a particular person starting the game.
Now, in condition v it is given that the person who wins more than two games does not win the first game.
-> Possibilities 1, 3, 4, 6, 7 and 8 are eliminated, leaving only possibilities 2 and 5. In both 2 and 5, R is the person who wins more than 2 games.
Therefore, R is the answer.
| 3. Tom, Dom and Rom are provided with a list of following words: IPF, PBS, QBE, UPF, WBU Each of them was told one letter of a certain word in a confident manner, and this letter was different for each of them. They were then told that the three letters shared with each of them could be arranged to form one of the words in the word list. Each of them was asked in turn (in the sequence Tom, Dom, Rom) if they knew which word the letters would construct and they all said ‘yes’. Can you identify the word which the letters spelt? |
Difficult |
| A. IPF B. QBE C. UPF D. Can’t be determined |
View Answer
Answer: Option A
Explanation:
The first person who claimed to know the word was Tom. He could say ‘yes’ only if he would have been told a letter which occurred only once in the given words i.e. I, S, Q, E, W.
Thus, the letter shared with Tom was one of the above 5.
In Dom’s turn, he knew that Tom was given one of the 5 letters – I, S, Q, E and W. He also knew that the word in question could not be UPF because this word did not have any of the 5 letters with Tom.
Further, Dom would know the word if the letter shared with him was U or F (in which case the word would be WBU or IPF respectively), OR if it was the second letter of QBE that occurred only once in the list of words i.e., Q or E.
(in which case, the word would be QBE).
Thus, in Rom’s turn, he knew that Tom knew one of the 5 letters: I, S, Q, E, W. He also knew that Dom knew one of the 4 letters: U, F, Q, E. He further knew that the word in question was neither UPF nor PBS.
So, Rom would know the word (which would be one of the three: WBU, IPF, QBE) if he was told the letter ‘P’ (in which case the word would be IPF) and would not know the word if he was told the letter B (in which case he would still be confused between WBU and QBE).
Hence, the answer is IPF.