| 1. A, B, C, D and E are five women with unique first and middle names as per the following conditions: i. Four of them have a first or middle name of San, three of them have a first or middle name of Tan, two of them have a first or middle name of Van, and one of them has a first or middle name of Zan. ii. Either A or B are both named Van or C and D are both named Van. iii. Out of B and C, either both are named Tan, or neither is named Tan. iv. D and E are not both named San. Who is named Zan? |
Difficult |
| A. B B. A C. D D. C |
View Answer
Answer: Option A
Explanation:
From condition iii, out of B and C, either both are named Tan, or neither is named Tan.
Let B and C be both named Tan (T); then two possibilities arise:
I. A and B are both named Van (V)
Let B and C both be not named Tan (T); then two possibilities arise:
| 2. P, Q and R are three football teams, which contest in a tournament, such that each team plays exactly once against each of the other teams. Also: i. The three final scores of the games comprised the first 6 natural numbers. ii. The difference between the higher scores of P and Q was one more than the lower scores of Q and R. iii. The highest total of a team’s two scores was accomplished by the team that lost the greatest number of games. Identify the team which had the highest total for its two scores. |
Difficult |
| A. P B. Q C. R D. Can’t be determined |
View Answer
Answer: Option C
Explanation:
From condition iii, we conclude that the team which loses both the matches and has the highest total of the two scores will score 5 in one of its matches, and lose against the team which scores 6 in that match. 5 will be the higher score of the losing team and 6 will be the higher score of the winning team. Further the team which has the highest total of the two scores can’t have 4 as its lower score because 4 has to be the score of a winning team. However, we need to try out possibilities with the next possible score i.e. 3, as team with the highest total of the two scores needs to have a total which is high.
Now apply condition ii, which can be expressed in the following equation:
|PH – QH| = 1+|QL – RL|
The only set of values satisfying this are:
|6-4| = 1+|2-3|
Therefore, PH = 6, PL= 1, QH = 4, QL = 2, RH = 5, RL = 3
Also, final results for the three games are:
P beats R -> 6 to 5
Q beats R -> 4 to 3
Q beats P -> 2 to 1
Now apply condition ii, which can be expressed in the following equation:
|PH – QH| = 1+|QL – RL|
The only set of values satisfying this are:
|6-4| = 1+|2-3|
Therefore, PH = 6, PL= 1, QH = 4, QL = 2, RH = 5, RL = 3
Also, final results for the three games are:
P beats R -> 6 to 5
Q beats R -> 4 to 3
Q beats P -> 2 to 1
| 3. A, B, C, D, E, F, G, H and I represent the 9 distinct decimal digits, 1 to 9, not necessarily in that order, such that: i. A+B+C=13 ii. C+D+E=13 iii. E+F+G=13 iv. G+H+I=13 What are the possible values which G can take? |
Medium |
| A. 1 & 5 B. 1 & 7 C. 3 & 9 D. None of these |
View Answer
Answer: Option B
Explanation:
